If A,B ,C are the angle of ` Delta ABC ` then ` cot A .cot B + cot B . "" cot C + cot

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If A,B,C are the angles off `DeltaABC`, then `cotA*cotB+cotB*cotC+cotC*cotA`= If A,B,C are the angles off `DeltaABC`, then `cotA*cotB+cotB*cotC+cotC*cotA`=
Show that cot(A-B) = (1+ cotA cotB)/(cotB -cotA). if cotA =½, cotB =2 and cotC =3 then cot(A-B-C)=3. Show that cot(A-B) = (1+ cotA cotB)/(cotB -cotA). if cotA =½, cotB =2 and cotC =3 then cot(A-B-C)=3.
Show cot(a + b) = (cot a cot b -1)/(cot b + cot a). Sum and Difference Identity Show cot(a + b) = (cot a cot b -1)/(cot b + cot a). Sum and Difference Identity
Show (cot(a - b)) = (cot a cot b +1)/(cot b - cot a). Sum and Difference Identity Show (cot(a - b)) = (cot a cot b +1)/(cot b - cot a). Sum and Difference Identity
Prove that cotB cotC + cotC cotA + cotA cotB = 1 Prove that cotB cotC + cotC cotA + cotA cotB = 1
Prove Cot A Cot B + Cot B Cot C + Cot A Cot C = 1 if A+B+C = π. Prove Cot A Cot B + Cot B Cot C + Cot A Cot C = 1 if A+B+C = π.
cot(a + B) = (cota*cotB - 1) / (cotB + cota) cot(a + B) = (cota*cotB - 1) / (cotB + cota)
Prove that:- cot(A+B+C)=(cotAcotBcotC-cotA-cotB-cotC)/(cotAcotB+cotBcotC+cotAcotC-1) Prove that:- cot(A+B+C)=(cotAcotBcotC-cotA-cotB-cotC)/(cotAcotB+cotBcotC+cotAcotC-1)