In given figure, ∠BAC=900 and segment AD⊥BC. Prove that AD2=BD×DC.

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In given Fig. ∠BAC=90° and segment AD⊥BC. Prove that AD^2=BD×DC. In given Fig. ∠BAC=90° and segment AD⊥BC. Prove that AD^2=BD×DC.
In the given figure, ∠BCA = 90° and AD ⊥ BC, then: In the given figure, ∠BCA = 90° and AD ⊥ BC, then:
In given figure, ∠ACB=900 and CD⊥AB. then prove that CB2/CA2=BDAD In given figure, ∠ACB=900 and CD⊥AB. then prove that CB2/CA2=BDAD
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