Find value of 2*C0 + square(2)*C1 /2 + cube(2)*C2 /3 + ... + [2 raised to power n+1]*Cn /(n+1).

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Simplify `C_0^2+C_1^2/2+C_2^2/3+...+C_n^2/(n+1)`. Simplify `C_0^2+C_1^2/2+C_2^2/3+...+C_n^2/(n+1)`.
`C_0/(1.2)+C_1/(2.3)+C_2/(3.4)+........C_n/((n+1)(n+ 2))=` `C_0/(1.2)+C_1/(2.3)+C_2/(3.4)+........C_n/((n+1)(n+ 2))=`
Find value of C0 + 2*C1 + 3*C2 + ... + (n+1)*Cn. Find value of C0 + 2*C1 + 3*C2 + ... + (n+1)*Cn.
Show that C0 + C1 / 2 + C2 / 3 + ... + Cn / (n+1) = { [2 raised to power n+1] - 1 } / (n+1). Show that C0 + C1 / 2 + C2 / 3 + ... + Cn / (n+1) = { [2 raised to power n+1] - 1 } / (n+1).
Basic Expansion problems - Binomial Theorem 2 - IB Maths Analysis and Approaches Basic Expansion problems - Binomial Theorem 2 - IB Maths Analysis and Approaches
Prove that : 1.〖C_0〗^2 + 3. 〖C_1〗^2 + 5. 〖C_2〗^2 + …… + (2n+1). 〖C_n〗^2 = (n+1)(2n)!/n!n! Prove that : 1.〖C_0〗^2 + 3. 〖C_1〗^2 + 5. 〖C_2〗^2 + …… + (2n+1). 〖C_n〗^2 = (n+1)(2n)!/n!n!
Prove that : C_0+2C_1+3C_2+………..+(n+1) C_n= (n+2)2^(n-1) Prove that : C_0+2C_1+3C_2+………..+(n+1) C_n= (n+2)2^(n-1)
Prove that : 2. C_0 + (2^2 〖.C〗_1)/2 + (2^3 〖.C〗_2)/3 + (2^4.C_3)/4 + …… + (2^(n+1).C_n)/(n+1) = (3^ Prove that : 2. C_0 + (2^2 〖.C〗_1)/2 + (2^3 〖.C〗_2)/3 + (2^4.C_3)/4 + …… + (2^(n+1).C_n)/(n+1) = (3^