x^2+y^2=6xy then prove that 2log(x+y) =logx+logy+3log2

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If x^2 + y^2 = 6xy, Prove that 2log(x+y) = logx + logy + 3log2 If x^2 + y^2 = 6xy, Prove that 2log(x+y) = logx + logy + 3log2
If `x^2 + y^2=6xy` prove that `2log(x+y) = logx+ logy + 3log2` If `x^2 + y^2=6xy` prove that `2log(x+y) = logx+ logy + 3log2`
if x² + y² = 6xy prove that 2log(x+y) = logx + logy + 3log2 if x² + y² = 6xy prove that 2log(x+y) = logx + logy + 3log2
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