if x² + y² = 6xy prove that 2log(x+y) = logx + logy + 3log2

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If x^2 + y^2 = 6xy, Prove that 2log(x+y) = logx + logy + 3log2 If x^2 + y^2 = 6xy, Prove that 2log(x+y) = logx + logy + 3log2
If `x^2 + y^2=6xy` prove that `2log(x+y) = logx+ logy + 3log2` If `x^2 + y^2=6xy` prove that `2log(x+y) = logx+ logy + 3log2`
x^2+y^2=6xy then prove that 2log(x+y) =logx+logy+3log2 x^2+y^2=6xy then prove that 2log(x+y) =logx+logy+3log2
If x²+y²=6xy, then prove that 2log(x+y)=logx+logy+3log2 | Real numbers | logarithms If x²+y²=6xy, then prove that 2log(x+y)=logx+logy+3log2 | Real numbers | logarithms
Real numbers | logarithms | If x² + y² = 25xy, then P.T 2 log (x + y) = 3 log 3 + log x + log y Real numbers | logarithms | If x² + y² = 25xy, then P.T 2 log (x + y) = 3 log 3 + log x + log y
If x^2 + y^2 = 6xy find 2 log (x+y) - log xy If x^2 + y^2 = 6xy find 2 log (x+y) - log xy
If x squre plus you square is equal to 6xy then prove 2log (x+y) = 3log2 +logx+logy If x squre plus you square is equal to 6xy then prove 2log (x+y) = 3log2 +logx+logy
#How to solve easily x2+y2 =6xy then 2log (x-y) =? #How to solve easily x2+y2 =6xy then 2log (x-y) =?