(a²+b²+c²)(x²+y²+z²) = (ax + by + cz)² To Prove : x/a=y/b=z/c

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if by+cz/b^2+c^2=cz+ax/c^2+a^2=ax+by/a^2+b^2 then prove that-x/a=y/b=z/c if by+cz/b^2+c^2=cz+ax/c^2+a^2=ax+by/a^2+b^2 then prove that-x/a=y/b=z/c
(a²+b²+c²)(x²+y²+z²)=(ax+by+cz)² find x:y:z (a²+b²+c²)(x²+y²+z²)=(ax+by+cz)² find x:y:z
If x²/(by+cz) = y²/(cz+ax) = z²/(ax+by) then a/(a+x)+b/(b+y)+c/(c+z)=? If x²/(by+cz) = y²/(cz+ax) = z²/(ax+by) then a/(a+x)+b/(b+y)+c/(c+z)=?
If x^2 /(by+cz) + y^2 /(cz+ax) +z^2 /(ax+by) find tℎe value of c/(2c+z) + b/(2b+y) + a/(2a+x) If x^2 /(by+cz) + y^2 /(cz+ax) +z^2 /(ax+by) find tℎe value of c/(2c+z) + b/(2b+y) + a/(2a+x)
x^2:by+cz=y^2:cz+ax=z^2:ax+by=1, prove that a/a+x+b/b+y+c/c+z=1 x^2:by+cz=y^2:cz+ax=z^2:ax+by=1, prove that a/a+x+b/b+y+c/c+z=1
Math olympiad Question | If 𝒙/𝒂+𝒚/𝒃+𝒛/𝒄=𝟏 and 𝒂/𝒙+𝒃/𝒚+𝒄/𝒛=𝟎 then 𝒙^𝟐/𝒂^𝟐 +𝒚^𝟐/𝒃^𝟐 +𝒛^𝟐/𝒄^𝟐 = ? Math olympiad Question | If 𝒙/𝒂+𝒚/𝒃+𝒛/𝒄=𝟏 and 𝒂/𝒙+𝒃/𝒚+𝒄/𝒛=𝟎 then 𝒙^𝟐/𝒂^𝟐 +𝒚^𝟐/𝒃^𝟐 +𝒛^𝟐/𝒄^𝟐 = ?
x²-yz/a²-bc=y²-zx/b²-ca=z²-xy/c²-ab then prove that x/a=y/b=z/c x²-yz/a²-bc=y²-zx/b²-ca=z²-xy/c²-ab then prove that x/a=y/b=z/c
if (x²-yz)/(a²-bc)=(y²-zx)/(b²-ca)=(z²-xy)/(c²-ab); then prove that x/a=y/b=z/c if (x²-yz)/(a²-bc)=(y²-zx)/(b²-ca)=(z²-xy)/(c²-ab); then prove that x/a=y/b=z/c