The solution of the differential equation (dx)/x + (dy)/y = 0(a) 1/x + 1/y = C (b) log(x) - log(y) =

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Solve the differential equation: `(1+y^2)(1+logx)dx+x dy=0` given that when `x=1,\\ y=1.`

Q263 Solve ylogydx + (x-logy)dy = 0

[y(1+1/x)+Cosy]dx+(x+logx-xSiny)dy=0 #ExactEquation #differentialequations

Solution of y * logy * dx + ( x - logy) * dy = 0

Solve : (1+y²)(1+ logx) dx + x dy = 0, given that y=1​ when x = 1

[y(1+1/x)+Cosy]dx+(x+logx-xSiny)dy=0 #ExactEquation L519 @MathsPulseChinnaiahKalpana

Exact Differential Equations | Differential Equations - (Part 1) | Problems & Solutions

Separable Differential Equation || y(1+x)dx+x(1+y)dy=0